In the given right angled triangle, AB=BC. Find all the three angles of the given triangle
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In the give figure AB = BC.
So, triangle ABC is an isosceles triangle .
Therefore AngleA = AngleC.
And
AngleB = 90°
So, ATQ, Angle( A. + B + C )= 180°[angle sum property of a triangle is 180°]
or Angle(90° + A + A) = 180°(since angle A = C)
or 2angleA = 180° - 90°
or 2angleA = 90°
Therefore angle A = 45°.
Therefore Angle A = C= 45° and angle B = 90°.
So, triangle ABC is an isosceles triangle .
Therefore AngleA = AngleC.
And
AngleB = 90°
So, ATQ, Angle( A. + B + C )= 180°[angle sum property of a triangle is 180°]
or Angle(90° + A + A) = 180°(since angle A = C)
or 2angleA = 180° - 90°
or 2angleA = 90°
Therefore angle A = 45°.
Therefore Angle A = C= 45° and angle B = 90°.
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