Question

In the given right-angled triangle ABC, ∠B = 90°. Find the value of x. if given that perpendicular =5cm base = x-3 and hypotenuse=x+2.? class 7​

Answer 1

Answer:

Step-by-step explanation:

Pythagoras theorem

$base^{2} + perpendicular^{2} = hypotenuse^{2}$

$(x-3)^{2} + 5^{2} = (x+2)^{2}$

$x^{2} - 6x + 9 + 25 = x^{2} +4x +4$

$x^{2} - x^{2} - 6x - 4x = 4 + 9 +25$

$-10x = 38\\x = -3.8$

Answer 2

Answer:

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Step-by-step explanation: