Question

In the given right angled triangle ABC, LB = 90° . Find the value of x .​

Answer 1

$\huge\bf\boxed{\boxed{\underline{\red{Answer!!}}}}$

$\huge\bold{Given}$

Right angle Triangle ∆ABC

AB = 5cm

BC = (x - 3)

AC = (x + 2)

$\huge\bold{To \:find }$

x value = ?¿

Now :

We know the formula :

$\huge\mathrm\pink{By \:pythagoras \:Formula}$

➪ $\mathrm\orange{(AC)² =(AB)² + (AC)²}$

➪ $\mathrm\orange{(x + 2)² =(x - 3)² + (5)²}$

➪ $\mathrm\orange{(x² + 4x + 4) = (x² - 6x + 9) + (25)}$

➪ $\mathrm\orange{\cancel{x²} + 4x + 4 = \cancel{x²} - 6x + 9 + 25}$

➪ $\mathrm\orange{4x + 4 = - 6x + 34}$

➪$\mathrm\orange{4x + 6x = 34 - 4}$

➪ $\mathrm\orange{10x = 30}$

➪ $\mathrm\orange{x = \frac{30}{10}}$

➪ $\mathrm\orange{x = \cancel\frac{30}{10}}$

➪ $\mathrm\orange{x = 3}$

$\huge\bf\boxed{\boxed{\underline{\red{x = 3}}}}$

Answer 2

Answer:

bhai you are write I don't know the answer sorry