Question

in the given,RQ is a tangent to the circle with the centre O if SQ=6cm and QR =4cm then find OR
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Answer 1

Sq = 6cm = Oq = 3cm

qr =4 cm , since rq is a tangent to the circle at q

Angle rqo =90 {tangent is perpendicular to the radius of a circle}

In triangle rqo ,{ Pythagoras theorem }

or^2=qr^2+oq^2

or^2=4^2+3^2

or^2=25

or=5cm