In the given triangle ABC, AD 1 BC. AB = 13 cm, BD = 5 cm, DC = 4 cm. Find the value of: (i) AD (ii) tan x cot y
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Answered by
3
Answer:
1) AB²=AD²+BD²(Pythagoras theorem)
13²=Ad²+5²
On simplifying....
AD=12cm
2)What are x and y?
Answered by
0
Answer:
by pythagorus theurum AD will be
AD^2=AB^2-DB^2
AD= ROOT OF 144
AD = 12
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