Question

In the given Triangle ABC, E is a point on AD. If angle AEB, angle ADB and angle ACD are equal to 180-k1,180-k2 and 180-k3 respectively then k1:k2:k3 equals

Answer 1

hey mate
here's the solution

Answer 2

Thank you for asking this question. Here is your answer:

k1 : k2 : k3

4∝ + 180 - k3 = 180

4∝ = k3

 

In AEB

∝ + 180 - k1 + ∝ = 180

 

2∝ = k1

k1 = 2∝ = k3/2

In the triangle ABC

∝ + k2 + 180 - k3 = 180

∝ = k3 - k2

k2 = k3 -∝

= 4∝ -∝

= 3∝

k1 = 2∝

k2 = 3∝

k3 = 4∝

If there is any confusion please leave a comment below.