in the given two lines ab and cd intersect at a point o if angle aoc +angle bod=70 find the measure of angle aod
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AOC = BOD. (vertically opposite angles)
AOC + BOD = 70
2(AOC) = 70
AOC = 35
AOD = 180 - AOC. (pair of linear angles)
AOD = 180 - 35
AOD = 145°
AOC + BOD = 70
2(AOC) = 70
AOC = 35
AOD = 180 - AOC. (pair of linear angles)
AOD = 180 - 35
AOD = 145°
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Hiteshbehera74:
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Question :-
In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.
Answer :-
Since AB is a straight line,
∴ ∠AOC + ∠COE + ∠EOB = 180°
or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]
or ∠COE = 180° – 70° = 110°
∴ Reflex ∠COE = 360° – 110° = 250°
Also, AB and CD intersect at O.
∴∠COA = ∠BOD [Vertically opposite angles]
But ∠BOD = 40° [Given]
∴ ∠COA = 40°
Also, ∠AOC + ∠BOE = 70°
∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°
Thus, ∠BOE = 30° and reflex ∠COE = 250°.
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