in the graph of kx+4y=12 passes through point (1,0), find k.
kartik45:
it is of maths
Answers
Answered by
1
Hi there !!
x = 1
y = 0
k× 1 + 4×0 = 12
k + 0 = 12
k = 12
x = 1
y = 0
k× 1 + 4×0 = 12
k + 0 = 12
k = 12
Answered by
0
given,
kx+4y=12 passes through the point (1,0)
such that, k(1)+4(0)=12
=>k=12
HOPE U CAN UNDERSTAND
PLS MARK IT AS BRAINLIEST
kx+4y=12 passes through the point (1,0)
such that, k(1)+4(0)=12
=>k=12
HOPE U CAN UNDERSTAND
PLS MARK IT AS BRAINLIEST
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