In the hare-tortoise race, the hare ran for 2 min at a speed of 7.5 km/h, slept for 56 min and again ran for 2 min at a speed of 7.5 km/h. Find the average speed of the hare in the race.
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since speed for 4 min is = 7.5 km/hr
and speed for 56 min = 0 km/hr
hence distance travelled at 4 min
= speed × time
= 7.5 km/hr× (4/60)hr
= 0.5 km
distance travelled at 56 min = 0
hence total distance travelled in 1 hr = 0.5 km
thus
average speed = total distance / total time
= 0.5km / 1 hr
= 0.5 km/hr
and speed for 56 min = 0 km/hr
hence distance travelled at 4 min
= speed × time
= 7.5 km/hr× (4/60)hr
= 0.5 km
distance travelled at 56 min = 0
hence total distance travelled in 1 hr = 0.5 km
thus
average speed = total distance / total time
= 0.5km / 1 hr
= 0.5 km/hr
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