In the hexagon ABCDEF, BC is parallel to ED and DC is parallel to EF. Angle DEF = 109 degrees and angle EFA= 95 degrees.
Angle FAB is equal to angle ABC.
Find the size of an angle EDC and angle FAB.
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Given : In the hexagon ABCDEF, BC is parallel to ED and DC is parallel to EF. ∠DEF = 109° and ∠EFA= 95° . ∠FAB = ∠ ABC
To find : ∠EDC & ∠FAB
Solution:
DC || EF
=> ∠DEF + ∠EDC = 180°
=> 109° + ∠EDC = 180°
=> ∠EDC = 71°
BC || ED
=> ∠EDC + ∠DCB = 180°
=> ∠DCB = 109°
Sum of all angles of Hexagon = 720°
=> 95° + 109° + 71° + 109° + ∠FAB + ∠ ABC = 720°
∠FAB = ∠ ABC given
=> 384 + ∠FAB + ∠ FAB = 720°
=> 2∠FAB = 336°
=> ∠FAB = 168°
∠EDC = 71° , ∠FAB = 168°
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