Physics, asked by balikakonkale6187, 1 year ago

In the isobaric process the ratio of heat supplied to the system and work done by the system for a diaatomic gas is

Answers

Answered by ketharin
1

For isobaric process and n = 1. dQ = 5/2 RdT + RdT = 7/2RdT. And dW = RdT. So ratio of dQ/dT is 7/2.

Hope it clears.
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Answered by nalinsingh
5

Hey !

In an isobaric process, heat supplied to the system,

                   dQ = nCpdt

And work done by the system,

                   dW = nRdT

Also, specific heat for diatomic gas at constant pressure,

                    Cp = 7/2 R

Therefore ratio of heat supplied to the system and work done by the system

         (dQ/dW) = nCpdT/nRdT = Cp/R

      =  7R/2 / R = 7/2

(or)       dQ : dW = 7:2

Good luck !

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