In the isochoric process, DH for a system is equal to
(a) P. ∆V (b) PV
(c) E + P. ∆V (d) ∆E
Answers
answer : option (d) ∆E
In the isochoric process, volume remains constant. but we know, workdone is the product of external pressure and change in volume.
so, in isochoric process, change in volume = 0
i.e., workdone = 0
from first law of thermodynamics,
∆H = ∆E + w = ∆E + 0
∆H = ∆E
hence option (d) is correct choice.
[isobaric process, pressure of system remains constant.
isothermal process, temperature of system remains constant.
adiabatic process, heat neither absorbs nor releases between system and surroundings. ]
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