Math, asked by malikrokadevsact, 5 months ago

In the isosceles triangle ABC, ∠A and ∠B are equal . ∠ACD is an exterior angle of triangle ABC . The measures of ∠ACB and ∠ACD are (5x – 35 )° and (20x +15)° respectively . Find the measures of ∠ACB and ∠ACD.​

Answers

Answered by Harshitagenius
0

Answer:

In the isosceles triangle ABC, ∠A and ∠B are equal. ∠ACD is an exterior angle of ∆ABC. The measures of ∠ACB and ∠ACD are (3x - 17) ° and (8x + 10) ° respectively. What are the values of ∠ACB and ∠ACD, and ∠A and ∠B?

Answered by shreenidhism25
2

Answer:

25/190

Step-by-step explanation:

5x-35+20x+15=180

25x-10=180

25x=180+10

25x=190

x=25/190

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