In the isosceles tringle tringle ABC, CD is the perpendicular bisector of AD.
(A)Draw the figure .
(B) Prove tringle ABC =tringle BDC [SAS theroem ].
(C)Prove <ACD=<BCD [SSS theroem ] ( hlep please)
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In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles
Step-by-step explanation:
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