Question

in the last second of freefall, body covers 3/4th of the total height of tower. From what height did it fall and how long was it in air?​

Answer 1

Answer:

Let the total time in free fall be t. Then, the distance covered just before the last second would be 1/4th the total distance, or t-1 seconds.

h(t)=1/2 gt²

h(t-1)=1/2g(t-1)²

1/4(1/2 gt²)=1/2 g(t-1)²

g/2t²=2g(t²-2t+1)

t²=4t²-8t+4

3t²-8t+4=0

(3t-2)(t-2)=0

t=2/3 or 2

We can ignore the 2/3rds seconds, and get a value for t as 2 seconds. So, the body fell for 2 seconds, and covered 4.9(4), or 19.6m

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Answer 2

Answer:

hi agniv are you from West Bengal?