Math, asked by yadavanita889, 1 year ago

In the letters of word attempt are written down at random probability all t's are together

Answers

Answered by ndahir7262
1

Answer:1/168

Step-by-step explanation:

In the word ATTEMPT we have 3t’s

no of ways of arranging ATTEMPT

                                          =7!/3!

                                          =840

when all t’s are consecutive=5

So required probability=5/840

                                        =1/168

Answered by amitnrw
0

Answer:

In the letters of word attempt are written down at random probability all t's are together = 1/7

Step-by-step explanation:

ATTEMPT

7 - Letters

T - 3 times

Total combination = 7!/3!  =  840

Lets consider TTT as single

then letters are A , E, M, P ,  (TTT)  = 5

Total Combination = 5! = 120

Probability = 120/840 = 1/7

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