Question

in the many years will rs 4000 amount to rs 5324 at the rate of 10% per annum compounded annually ?

Answer 1

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CI=p {(1+r)^n-1}

5324-4000=4000 {(1+10/100)^n}-4000

5324=4000 (1+1/10)^n

5324/4000=(11/10)^n

1331/1000=(11/10)^n

(11/10)^3=(11/10)^n

n=3

hence 3 years

Answer 2

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Here is your answer
P = Rs 4000
A = Rs 5324
R = 10% p.a

As we know the formula
A = P(1+ R/100)^n
$5324 = 4000 \times (1 + \frac{10}{100} ) {}^{n} \\ \\ \frac{5324}{4000} = (1 + \frac{1}{10} ) {}^{n} \\ \\ \frac{1331}{1000} = ( \frac{10 + 1}{10 } ) {}^{n} \\ \\ ( \frac{11}{10} ) {}^{3} = ( \frac{11}{10} ) {}^{n} \\ \\ same \: base \: so \: power \: is \: same \\ \\ n = 3$
Therefore Time is 3 years

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