In the network shown below, find the equivalent resistance between A and B
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first find the resistance of middle they are connected into series
RS=3R+3R
RS = 6R
and this 6R resistor is parallel to B side resistor
Rp
= 3R×6R/6R+3R
= 2R
so finally resistance between A and B is
RS1
=2R+R
=3R
so equivalent resistance between A and B is 3R
RS=3R+3R
RS = 6R
and this 6R resistor is parallel to B side resistor
Rp
= 3R×6R/6R+3R
= 2R
so finally resistance between A and B is
RS1
=2R+R
=3R
so equivalent resistance between A and B is 3R
Answered by
0
Answer:
3R
Explanation:
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