Question

In the network shown in the figure, the equivalent
capacitance between points A and B is​

Answer 1

Explanation:

EQUIVALENT CAPACITANCE IS [ 3C / 4 ]

Answer 2

Given:

Between points A and B, there are three capacitors connected in parallel which are connected to the fourth capacitor in series.

Formula Used:

When capacitors are connected in parallel, the equivalent capacitance is given by:

$C=C_1+C_2+C_3+....$

When capacitors are connected in series, the equivalent capacitance is given by:

$C=(\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}+....)^{-1}$

Calculations:

Between points A and B, there are three capacitors connected in parallel:

$C'=C+C+C\\C'=3C$

C' is connected in series with C. Equivalent capacitance between point A and B would be:

$C_e=(\frac{1}{C'}+\frac{1}{C})^{-1}\\C_e=(\frac{1}{3C}+\frac{1}{C})^{-1}\\C_e=\frac{3C}{4}$

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