Question

In the network shown in the figure, the equivalent resistance
between A and B is
(A) 10R
(B) (6/11) R
(C) (25/12) R
(D) (50/11) R​

Answer 1

Between A and B :- R , 2R , 3R all are in parallel.

$\frac{1}{Req} = \frac{1}{R} + \frac{1}{2R} + \frac{1}{3R}$

$\frac{1}{Req} = \frac{2 + 1}{2R} + \frac{1}{3R}$

$\frac{1}{Req} = \frac{3}{2R} + \frac{1}{3R}$

$\frac{1}{Req} = \frac{9+ 2}{6R}$

$\frac{1}{Req} = \frac{11}{6R}$

$Req= \frac{6R}{11}$

so option (B) (6/11)R is correct answer

hope it helps

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