in the number pattern 66, 127, 218 t,the value of t will be
Answers
There is a definite pattern in the series. Please have a close look at it.
66, 127, 218, t
The sequence is dealing with cubes.
a(n) = n^3 + 2
⇒ a(4) = 4³ + 2
= 64 + 2
= 66
a(5) = 5³ + 2
= 125 + 2
= 127
a(6) = 6³ + 2
= 216 + 2
= 218
a(7) = 7³ + 2
= 343 + 2
= 345
So, the value of t is 345.
Answer.
In the series 66, 127, 218, t the value of 't' is 345
Step-by-step explanation:
Given data
Series - 66, 127, 218 t
To find the value of 't' in the above series
It is clear that the given series is in the form of n³ + 2
If we consider n = 0, 1, 2, 3, 4, 5, 6, 7
n = 0 => n³+ 2 = 0+ 2 = 2
n = 1 => n³+ 2 = 1 + 2 = 3
n = 2 => n³+ 2 = 8 + 2 = 10
n = 3 => n³+ 2= 27+ 2 = 29
n = 4 => n³+ 2 = 64 + 2 = 66
n = 5 => n³+ 2 = 125 + 2 = 127
n = 6 => n³+ 2 = 216 + 2 = 218
n = 7 => n³+ 2 = 343 + 2 = 345
n = 8 => n³+ 2 = 512 + 2 = 514
Therefore the value of "t" in the series 66, 127, 218 t, is 345
To Learn More ...
1) Find the missing term(s) in the series given below: 8, 15, 36, 99, ?, 855
https://brainly.in/question/5685796
2) Find the missing term in the following series: 1, 4, 27, 16, _, 36, 343
https://brainly.in/question/635929