In the parallelogram abcd, ab = 21, bc = 13 and bd = 14. Find the length ac. (the diagonals of a parallelogram bisect each other)
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A=√s(s-a)(s-b)(s-c)
1/2×a+b+c
1/2(20+13+21)
1/2×54
s=27
√27(27-20)(27-13)(27-21)
s=√15876
s=12
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