Question

In the parallelogram abcd , diagonal ac , and bd intersect at o and ac = 6.4 cm and bd = 5.8 cm . find the oa and ob ( )

Answer 1

Following the rule,

=>Diagonal of a parllelogram bisect each other.

So,AC bisect BD at O

AC=AO+OC

AC=AO+AO

6.4=2AO

6.4/2=AO

3.2cm=AO

BD=BO+OD

BD=BO+BO

5.8=2BO

5.8/2=BO

2.9cm=BO