Question

In the parallelogram PQRS, PQ = 8 cm and QR = 5 cm. Find the perimeter of the parallelogram.​

Answer 1

Given :

• In a parallelogram PQRS,
• PQ = 8 cm
• QR = 5 cm

To Find :

• The perimeter of the parallelogram.

Solution :

As we know that, opposite sides of a parallelogram are equal.

$\dashrightarrow \: \: \bf \: PQ = RS = 8 \: cm \:$

$\dashrightarrow \: \: \bf \: QR = PS = 5 \: cm \:$

Now calculating the perimeter,

Formula :

• $\underline{ \boxed{ \rm{Perimeter_{(parallelogram)} = 2(a + b) }}}$

Inserting the values,

$\dashrightarrow \: \: \bf \: Perimeter_{(parallelogram)} = 2(8 + 5) \: cm$

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$\dashrightarrow \: \: \bf \: Perimeter_{(parallelogram)} = 2 \times 13 \: cm$

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$\dashrightarrow \: \: \underline{ \boxed{ \bf{ \blue{ Perimeter_{(parallelogram)} = 26 \: cm}}}}$

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$\therefore \: \underline{ \sf{Perimeter \: of \: the \: parallelogram \: = \bf{26 \: cm} }}$

Diagram :

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf Q}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf R}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf P}\put(-0.2,2.3){ \sf 8\:\:cm }\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf S}\put(3,0.5){\sf 5 cm}\end{picture}$

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Know more!

Some important formulae related to a parallelogram :-

• Area of parallelogram = base × height
• Perimeter of parallelogram = 2 (a + b)