Question

in the Parallelogram RISE, SN is parallel to RI and SM is parallel to RE. Find SEM, NSF, SIN​

Answer 1

Extend PQ to Y and draw LM || ST

through R.

∠TSX = ∠QXS

[Alternate angles]

⇒ ∠QXS = 130°

∠QXS + ∠RXQ = 180°

[Linear pair axiom]

⇒ ∠RXQ = 180° – 130° = 50° …(1)

∠PQR = ∠QRM [Alternate angles]

⇒ ∠QRM = 110° …(2)

∠RXQ = ∠XRM [Alternate angles]

⇒ ∠XRM = 50° [By (1)]

∠QRS = ∠QRM – ∠XRM

= 110° – 50° = 60° Ans.

Answer 2

Answer:

in the Parallelogram RISE, SN is parallel to RI and SM is parallel to RE. Find SEM, NSF, SIN

answer is 110°-50°=60°