Question

In the parallelorgam DEAR, if <DEA = 110 degree
then, the find of the value of EDR ?​

Answer 1

Step-by-step explanation:

Answer:

In a parallelogram ABCD,

\angle A=\angle C = 110∠A=∠C=110

and

\angle B=\angle D = 70∠B=∠D=70

Step-by-step explanation:

Given ABCD is a parallelogram.

and

\angle A =110∠A=110 -----(1)

i ) We know that,

/* Sum of adjacent angles are supplementary in a parallelogram */

\angle A+ \angle B = 180∠A+∠B=180

\implies110+\angle B = 180⟹110+∠B=180

\implies \angle B = 180-110⟹∠B=180−110

\implies \angle B = 70°⟹∠B=70° ---(2)

/* In a parallelogram ,

Opposite angles are equal */

Therefore,

In a parallelogram ABCD ,

\angle A=\angle C = 110∠A=∠C=110

and

\angle B=\angle D = 70∠B=∠D=70

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