In the parllelogram pqrs if p=2x+25and q =3x-5 find the value of x
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Since the opposite angles of parallelogram are supplementary
p+q=180
2x+25+3x-5=180
5x+20=180
therefore 5x=160
THEREFORE x=32
p+q=180
2x+25+3x-5=180
5x+20=180
therefore 5x=160
THEREFORE x=32
Answered by
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Now, given that quad. pqrs is a parallelogram.
We know that in a parallelogram , the adjacent angles are supplementary because the opp.sides are parallel to each other. and thus, by the co-interior angles property , this is the result.
∴ ∠p + ∠q = 180°
∴ 2x + 25 + 3x - 5 = 180
∴ 5x + 20° = 180°
∴ 5x = 160°
∴ x = 32°
Hence, the value of x is 32°.
Hope this helps you !
# Dhruvsh
We know that in a parallelogram , the adjacent angles are supplementary because the opp.sides are parallel to each other. and thus, by the co-interior angles property , this is the result.
∴ ∠p + ∠q = 180°
∴ 2x + 25 + 3x - 5 = 180
∴ 5x + 20° = 180°
∴ 5x = 160°
∴ x = 32°
Hence, the value of x is 32°.
Hope this helps you !
# Dhruvsh
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