in the perimeter of a square is equal to the perimeter of a rectangle then find the area of rectangle if the side of a square is 8cm and breath of rectangle is
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area of sq=S^2
area rectangle = (l*b)
perimeter of sq =4(8)=32
and of rectangle=2(l+b)
L+B=16 now divide by 2
L+B/2=8 square on both side 8^2=area of sq=S^2
128=L+B+2LB L+B=16
112=2LB
LB=56
area rectangle = 56cm.
solve quadratic equa for B
b^2-16B+56=0
Step-by-step explanation:
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