Question

In the quadratic equation x^2-2kx+3k+4=0, k is a real number.
a)If the equation has equal roots, find the values of k and solve the equationfor each value of k
b)if the equation has no real roots, find the range of values of k.

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

x2+kx+k=0 has only one solution.

∴ The discriminant b2−4ac=0

∴k2−4k=0

⇒k(k−4)=0

∴k=0 or k=4

So for k=0 or k=4 the equation x2+4x+4=0 has only one solution.