Chemistry, asked by jeyadurai1974, 9 months ago

In the reaction a and b is to C and equilibrium is established them the pressure the is equal in the other equilibrium which day is exchange change day if this

Answers

Answered by harleen1067a
0

Answer:

A+B⇌C+D. If initially the concentraion of A and B are both equal but at equilibrium, concentration of D will be twice of that of A, then the equilibrium constant of the reaction will be 4.

                                                                          A+B⇌C+D

Initial concentration (M)            t=0             a         a          0     0

Equilibrium concentration (M)  t  

eq.

​  

            a−x       a−x   x   x

At equilibrium, concentration of D will be twice of that of A.

x=2(a−x)

x=2a−2x

3x=2a

x=  

3

2

​  

a

The equilibrium constant

K=  

[A][B]

[C][D]

​  

 

K=  

(a−x)(a−x)

x×x

​  

 

K=  

(a−  

3

2

​  

a)(a−  

3

2

​  

a)

3

2

​  

a×  

3

2

​  

a

​  

 

K=  

(  

9

1

​  

a  

2

)

9

4

​  

a  

2

 

​  

 

K=4

Explanation:

Answered by rinikapriya0110
2

Answer:

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Explanation:

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