Chemistry, asked by SteveLosive, 4 months ago

In the reaction A --> products, at t=0, [A] = 0.1565 M. After 60.00sec, [A] = 0.1498 M, and after 2.00 min., [A] = 0.1433 M. Calculate the average rate of the reaction during the first minute and during the second minute.

Answers

Answered by ChitranjanMahajan
0

The average rate of the reaction during the first minute and during the second minute is 0.0067 M/min and 0.00132 M/min respectively.

Given,

t=0, [A] = 0.1565 M

t=60 sec, [A] = 0.1498 M

t=2.00 min., [A] = 0.1433 M

To find,

Average rate of the reaction during t=1min

Average rate of reaction during t=2min

Solution,

We can simply solve this problem, using the following process:

Average rate of reaction = Change in concentration / Change in time

Now,

Average rate of the reaction during the first minute:

r₁=0.1498 - 0.1565 M / 1 min

r₁ = - 0.0067 M/min

Average rate of the reaction during the second minute:

r₂ = 0.1433 M -  0.1565 M / 2 min

r₂ = - 0.0132 M/min.

Hence, the average rate of the reaction during the first minute and during the second minute is 0.0067 M/min and 0.00132 M/min respectively.

#SPJ1

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