Question

In the reaction :
A □(→┴K₂Cr₂O₇) acetone □(→┴oxidation) acetic acid
A is
(a) 1- propanol (b) 2-butanol
(c) 2-propanol (d) ethanol

Answer 1

Answer:

A is (d) ethanol

Explanation:

ethanol in presence of k2cr2o7 undergoes oxidation to form ethanoic acid (acetic acid)

Answer 2

A is :

Reaction : A (→┴K₂Cr₂O₇) acetone (→┴oxidation) acetic acid

• We know that K₂Cr₂O₇ oxidizes 2° alcohol into ketonic group.

• Further oxidation of ketone containing compound gives carboxylic acid.

• Therefore A should be 2° alcohol.

• In above options there are two 2° alcohols, 2-butanol and 2-propanol.

• But acetone contains only 3 carbon. Hence, A is 2-propanol.