Question

In the reaction , be2c +xh2O -----> ybe (Oh)2+Ch4

write the value of x nd y?

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Answer 1

Heya !!

Here is your answer

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The reaction is :-

Be2C + 4H2O ------------ 2Be(OH)2 + CH4

So, the value of x= 4 and y=2.

Answer 2

The value of x and y is 4 and 2.

• Beryllium carbide on reaction with water forms beryllium hydroxide along with methane gas.
• The balanced chemical equation of the reaction is as follows-
• $Be_2C+4H_2O\rightarrow 2Be(OH)_2+CH_4$
• Hence in this reaction, one mole of Beryllium carbide reacts with four moles of water to form two moles of beryllium hydroxide along with one mole of methane gas.
• Thus the value of x and y is 4 and 2.