Question

In the reaction, Be2C + xH2O → yBe(OH)2+ CH4 what will be the values of x and y ​

Answer 1

Answer: x=4,y=2

Explanation:

$Be_{2}C+xH_{2}O =>yBe(OH)_2}+CH_{4} \\Or, Be_{2}C+4H_{2}O =>2Be(OH)_2}+CH_{4}$

Total Be in LHS=2, so, y=2

and after putting y=2 in RHS, the total 'O' in RHS is 4, so, x=4

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