Chemistry, asked by karanchavan021, 10 months ago

In the reaction C2O 2

4

+ MnO 

4

+ H+ Mn+2 + CO2 the reductants is:​

Answers

Answered by mendheravindra
1

Answer:

MnO

4

=2,C

2

O

4

2−

=5,H

+

=16

Explanation:

The unbalanced redox reaction is MnO

4

+C

2

O

4

2−

+H

+

→Mn

2+

+CO

2

+H

2

O

Balance C atoms.

MnO

4

+C

2

O

4

2−

+H

+

→Mn

2+

+2CO

2

+H

2

O

The oxidation number of Mn decreases from +7 to +2.

The decrease in the oxidation number is 7−2=5

The oxidation number of C increases from +3 to +4.

The increase in the oxidation number for 1 C atom is 4−3=1

The increase in the oxidation number for 2 C atom is 2×1=2

To balance the increase in the oxidation number with decrease in the oxidation number, multiply Mn containing species with 2 and C containing species with 5.

2MnO

4

+5C

2

O

4

2−

→2Mn

2+

+10CO

2

Balance O atoms by adding 8 water molecules to the products side.

2MnO

4

+5C

2

O

4

2−

→2Mn

2+

+10CO

2

+8H

2

O

Balance H atoms by adding 16 H

+

ions to the reactants side.

2MnO

4

+5C

2

O

4

2−

+16H

+

→2Mn

2+

+10CO

2

+8H

2

O

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