Question

In the reaction given below the reducing agent is:-,​

Answer 1

2CrO

4

−2

+2H

+

⟶CrO

7

2−

+H

2

O

Here Cr

+2

is converting into Cr

+6

It is getting oxidised. Thus CrO

4

2−will act as a reducing agent.

Cr

O 2− →Cr is in+6 Oxidation state.

Cr 2 Ol2−

will act as an oxidising agent.