Chemistry, asked by sriganeshandco973, 1 year ago

In the reaction n2 +02= 2no at equilibrium the concentrations of n2, o2, and no are 0.25. 0.05 and 1 m respectively. Calculate initial concentrations of n2, and o2.

Answers

Answered by antiochus
0

Answer:

Capacity of the container=2.5L

Initial moles given are

N_{2} =2moles

O_{2} =4moles

moles of N2 used in equilibrium=0.5moles

The equilibrium moles of NO is 2*0.5=1

Molar concentration of nitric oxide is 1/2.25=0.4M/L

Answered by CarlynBronk
2

The initial concentration of N_2\text{ and }O_2 are 0.75 M and 0.55 M respectively.

Explanation:

We are given:

Equilibrium concentration of NO = 1 M

Equilibrium concentration of N_2 = 0.25 M

Equilibrium concentration of O_2 = 0.05 M

For the given chemical equation:

                  N_2+O_2\rightleftharpoons 2NO

Initial:            a     b        -

At eqllm:     a-c    b-c     2c

Calculating the value of 'c'

2c=1\\\\c=0.5

Calculating the value of 'a' and 'b', we get:

For 'a'

a-c=0.25\\\\a-0.5=0.25\\\\a=0.75M

For 'b'

b-c=0.05\\\\b-0.5=0.05\\\\b=0.55M

Learn more about chemical equilibrium:

https://brainly.in/question/12361151

https://brainly.com/question/14182284

#learnwithbrainly

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