In the reaction, PCl_5(g)⇌PCl_3(g)+Cl_2(g) , the amounts of PCl_5, PCl_3 and Cl_2 are 2 mole each at equilibrium and the total pressure is 3 atmosphere. The equilibrium constant, K_p is
Answers
Answered by
2
Answer:
Total pressure is 3 atm.
Total number of moles =2+2+2=6
Number of moles of PCl
5
=2
Mole fraction of PCl
5
=
6
2
=0.333
Partial pressure of PCl
5
=0.333×3 atm=1 atm.
Number of moles of PCl
3
=2
Mole fraction of PCl
3
=
6
2
=0.333
Partial pressure of PCl
3
=0.333×3 atm=1 atm.
Number of moles of Cl
2
=2
Mole fraction of Cl
2
=
6
2
=0.333
Partial pressure of Cl
2
=0.333×3 atm=1 atm.
The equilibrium constant K
p
=
P
PCl5
P
PCl3
×P
Cl2
K
p
=
1
1×1
=1
Similar questions