Question

In the reaction PCl5 -----> PCl3 Cl2 the partial pressure of PCl3, Cl2, PCl5 are 0.3,0.2 and 0.6 ATM respectively. If partial pressure of PCl3 and Cl2 was increased twice, what will be the partial pressure of PCl5 in atm

(a) 0.3
(b) 1.2
(c) 2.4
(d) 0.15

Answer 1

Answer: The correct option is (c).

Explanation:

$PCl_5\rightleftharpoons PCl_3+Cl_2$

Given:

$p_{PCl_5}=0.6 atm,p_{PCl_3}=0.3 atm,p_{Cl_2}=0.2 atm$

Expression of $K_p$ is written as :

$K_p=\frac{p_{PCl_3}\times p_{Cl_2}}{p_{PCl_5}}=\frac{0.3atm\times 0.2atm}{0.6 atm}=0.1$

Partial pressure of $PCl_5$ when partial pressure of $PCl_3$ and $Cl_2$ was increased twice:

$K_p=\frac{2p_{PCl_3}\times 2p_{Cl_2}}{p'_{PCl_5}}$

${p'_{PCl_5}}=\frac{2p_{PCl_3}\times 2p_{Cl_2}}{K_p}=\frac{2\times 0.3atm\times 2\times 0.2atm}{0.1 atm}=2.4 atm$

The partial pressure of $PCl_5$ in 2.4 atm

Answer 2

Answer:

answer is 2.4

Explanation:

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