Chemistry, asked by Enakashi304, 11 months ago

In the reaction with HCl, an alkene reacts in accordance with
the Markovnikov's rule, to give a product 1-chloro-1-
methylcyclohexane. The possible alkene is : [2015 RS]
(c) (a) and (b)

Answers

Answered by brokendreams
0

Both a and b are the options.

Explanation:

  • Markovnikov's addition is the SN1 addition through the carboncation formation.
  • The stability of the carboncation is as 3° > 2° > 1°.
  • As the 1st compound given in the option undergoes protonation around the double bond, the 3° carboncation is formed.
  • In the 2nd compound given in the option undergoes protonation to form a 2° cation.
  • This undergoes rearrangement to form the 3° carboncation and forms the same product.

For more information about Markovnikov's addition,

https://brainly.in/question/9005176

mechanism of markovnikov and anti markovnikov rule​ - Brainly.in

https://brainly.in/question/2340520

Anti markovnikov addition of hbr is not observed in which of following (a) propene (b) but-i-ene (c)but-2-ene (d) pent-2- Ene

Answered by Anonymous
0

Explanation:

In the reaction with HCl, an alkene reacts in accordance with

the Markovnikov's rule, to give a product 1-chloro-1-

methylcyclohexane. The possible alkene is : [2015 RS]

(c) (a) and (b)✔️

Similar questions