In the reaction with HCl, an alkene reacts in accordance with
the Markovnikov's rule, to give a product 1-chloro-1-
methylcyclohexane. The possible alkene is : [2015 RS]
(c) (a) and (b)
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Both a and b are the options.
Explanation:
- Markovnikov's addition is the SN1 addition through the carboncation formation.
- The stability of the carboncation is as 3° > 2° > 1°.
- As the 1st compound given in the option undergoes protonation around the double bond, the 3° carboncation is formed.
- In the 2nd compound given in the option undergoes protonation to form a 2° cation.
- This undergoes rearrangement to form the 3° carboncation and forms the same product.
For more information about Markovnikov's addition,
https://brainly.in/question/9005176
mechanism of markovnikov and anti markovnikov rule - Brainly.in
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Anti markovnikov addition of hbr is not observed in which of following (a) propene (b) but-i-ene (c)but-2-ene (d) pent-2- Ene
Answered by
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Explanation:
In the reaction with HCl, an alkene reacts in accordance with
the Markovnikov's rule, to give a product 1-chloro-1-
methylcyclohexane. The possible alkene is : [2015 RS]
(c) (a) and (b)✔️
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