Question

in the redox reaction 2k(s)+f2(g)=2kf(s) oxidation of which substance takes place​. Justify

Answer 1

just wanna tell you about OIL RIG

oxidation is loss & reduction is gain

Answer 2

The substance getting oxidized is potassium.

Explanation:

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

For the given chemical reaction:

$2K(s)+F_2(g)\rightarrow 2KF(s)$

The half chemical equation for the above reaction follows:

Oxidation half reaction:  $K\rightarrow K^++e^-$    ( × 2)

Reduction half reaction:  $F_2+2e^-\rightarrow 2F^-$

The substance that is getting oxidized is potassium and the substance getting reduced is fluorine.

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