Physics, asked by sanjibkumarmohanta30, 11 months ago

In the relation F=Q1Q2/r^2. what is the value of K in the free space.

Answers

Answered by Anonymous
11

 \underline{ \boxed{ \bold{ \huge{ \purple{Answer}}}}} \\  \\  \dagger \:   \rm{ \red{To \: Find}} \\  \\  \implies \rm \: value \: of \: k \: in \: F =  \frac{kq{ \tiny{1}}q{ \tiny{2}}}{ {r}^{2} }  \\  \\  \dagger \rm  \: \red{Calculation} \\  \\  \implies \rm \: k =  \frac{1}{4 \pi \epsilon{ \tiny{o}}}  \\  \\   \implies \rm \:  \epsilon{ \tiny{o}} = permittivity \: of  \: free \: space = 8.85 \times  {10}^{ - 12}   \frac{ {C}^{2} }{N {m}^{2} }  \\  \\  \implies \rm \: k =  \frac{1}{4 \times 3.14 \times 8.85 \times  {10}^{ - 12} }  = 8.99 \times {10}^{9}  \approx9 \times  {10}^{9}  \frac{N {m}^{2} }{ {C}^{2} }  \\  \\  \clubsuit \:  \:  \boxed{ \rm{ \orange{k = 9 \times  {10}^{9}  \:  \frac{N {m}^{2} }{ {C}^{2} } }}}

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