Question

In the relation p=alpha/beta e^alphax/nr theta. Find dimensional formula of bota

Answer 1

Answer:

     [L]^2

Remark, Dimension of pressure

  [M][L]^(-1)[T]^(-1)

Step-by-step explanation: Dear Student,

Given that,

     $p = \frac{\alpha }{\beta } e^{\frac{-\alpha x}{kc} }$

Assume, theta = c

                k = nr

Where,

    p is pressure

    x is distance

    c is theta means temperature.

    k is Boltzman constant

Dimensions of

    $k = [M][L]^{2}[T]^{-2}[k]^{-1}$

          c = [k]

      $kc =  [M][L]^{2}[T]^{-2}$ = Dimension of alphax

  Dimension of x = [L]

Dimension of alpha =[M][L]^2[T]^(-2)

DIMENSION OF ALPHA/BETA = DIMENSION OF P

Dimension of Beta = [L]^2

Hope it helps

With Regards