Question

In the reversible reaction A+B C+D, the concentration of each C and D at equilibrium was
0.8 mole/ litre, then the equilibrium constant K will be

a) 6.4
b) 0.64
d) 16
c) 1.6
​

Answer 1

Explanation:

In the reversible reaction A + B ⇔ C + D, the concentration of each C and D at equilobrium was 0.8 mole/litre, then the equilibrium constant Kc will be. ...

Suppose 1 mole of A and B is each taken, then 0.8 mole/litre of C and D each formed remaining concentration of A and B will be (1-0.8)=0.2 mole/litre

Answer 2

Explanation:

In the reversible reaction A + B ⇔ C + D, the concentration of each C and D at equilobrium was 0.8 mole/litre, then the equilibrium constant Kc will be. ... Suppose 1 mole of A and B is each taken, then 0.8 mole/litre of C and D each formed remaining concentration of A and B will be (1-0.8)=0.2 mole/litre.