Question

in the right angled isosceles triqngle if the square of longest side 72m.find the length of two sides

Answer 1

Let ABC be the right angled isosceles triangle right angled at B whose square of the longest side is 72m

In ∆ABC by Pythagoras theorem we get,

AC^2=AB^2+BC^2

72= AB^2+AB^2. (AB=BC & AC^2=72)

72=(AB+AB)(AB-AB). (a^2+b^2= (a+b)(a-b))

72= 2AB

AB= 36

Therefore, BC=AB=36

Answer 2

Answer:

36

Step-by-step explanation:

Let ABC the right angled isosceles triangle right angled at B whose square of the longest side is 72 cm.

In triangle ABC by Pythagoras theorem we get,

AC^2=AB^2+BC^2

72=AB^2+BC^2

72= 2AB

AB=36

THEREFORE, BC=AB=36