Question

in the sequence of 3 consecutive natural number, product of two alternate number is one less than the square of middle number.
1×3=2skoyar -1
8×10=9skoyar -1
using this, find
a)99×101=------
b)49×51=----
c)199×201=----​

Answer 1

SOLUTION

GIVEN

In the sequence of 3 consecutive natural number, product of two alternate number is one less than the square of middle number.

1 × 3 = 2² - 1

8 × 10 = 9² -1

TO DETERMINE

Using this, find

a) 99×101 =

b) 49×51 =

c) 199×201 =

EVALUATION

Here it is given that In the sequence of 3 consecutive natural number, product of two alternate number is one less than the square of middle number.

1 × 3 = 2² - 1

8 × 10 = 9² -1

Now

a) 99×101

= 100² - 1

= 10000 - 1

= 9999

b) 49×51

= 50² - 1

= 2500 - 1

= 2499

c) 199×201

= 200² - 1

= 40000 - 1

= 39999

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