In the shape of a straight path across a river makes an angle of 60° with the width of the river if the length of the bridge is 100 M find the width of the river
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Let AB be the width of the river and AC be the bridge.
In the triangle ABC,
Cos 60 = AB / AC
1 / 2 = AB / 100 => AB = 50m
Hence the width of the river is 50 m.
In the triangle ABC,
Cos 60 = AB / AC
1 / 2 = AB / 100 => AB = 50m
Hence the width of the river is 50 m.
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Given:
A bridge in the shape of a straight path across a river makes an angle of 60° with the width of the river
The length of the bridge = 100 m
To Find:
The width of the river
Solution:
The width of the river is 50m.
In the diagram attached below, AB represents the bridge that makes an angle of 60° with the width BC of the river.
Since ΔABC is a right-angled triangle with ∠C = 90°,
We can apply trigonometry to find an unknown side.
cos Ф = Base / Hypotenuse
For the given figure,
cos 60° = BC / AB
Substituting cos 60° = 1/2 and AB = 100m,
1/2 = BC / 100
or BC = 100/2
= 50m
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