A person pays 975 as monthly installment each installement being less than former by 5 the amount paid in first installment is 100 . In what time the amount will be paid
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Answered by
109
As given in problem, A=100, D=-5
Formula is:
Sum of AP = n/2 [2a+(n-1)d]
Therefore,
975 = n/2 [200+(n-1)-5]
1950 = n(200-5n+5)
1950 = 205n-5n^2
5n^2-205n+1950 = 0
n^2-41n+391 = 0
n^2-26n-15n+390 = 0
n(n-26) - 15(n-26) = 0
Hence,
n = 15 or 26.
So,
n = 15 months.
Formula is:
Sum of AP = n/2 [2a+(n-1)d]
Therefore,
975 = n/2 [200+(n-1)-5]
1950 = n(200-5n+5)
1950 = 205n-5n^2
5n^2-205n+1950 = 0
n^2-41n+391 = 0
n^2-26n-15n+390 = 0
n(n-26) - 15(n-26) = 0
Hence,
n = 15 or 26.
So,
n = 15 months.
Answered by
3
Given; A person pays 975 as monthly instalments each instalment is less than the eye amount paid in the first instalment is 100
To Find; What is the amount that will be paid
Solution; It is given that A person pays 975 as monthly instalments each instalment is less than the former by 5 the amount paid in the first instalment is 100
First instalment a= 100
Decrement d=5
Total amount Sn= 975
solving this we get n as 15
Hence the amount will be paid in fifteen months
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