Question

In the shown circuit, all five resistors have the same value 100 ohms and each cell has an electromotive force of 15 volts. Find the potential difference (in volts) between points b and
a.

Answer 1

Answer:

Sorry I am not able to answer because I forgot this concept .

Answer 2

The potential difference (in volts) between points B and A is -3 Volts.

Explanation:

For the open circuit,

Let the current flowing in the circuit be 'I'.

By applying Kirchhoff's law, we get the following equation

5IR = 3 × 15

I = $\frac{45}{5R} = \frac{45}{500} = 9 \times 10^{-2} A$

The current in the circuit is 9 × 10⁻² ampere.

The voltage difference between them is as follows:

$V_{AB} = V_{A} - V_{B} = -2 \times 100 \times 9 \times 10^{-2} + 15=-3V$

Hence, the potential difference (in volts) between points B and A is -3 Volts.

The question can be completed as follows: