in the shown figure P A is perpendicular to a b and q b is perpendicular to a b for the ap is equal to BQ prove that who is the midpoint of Ab and PQ
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hence poq is the mid hence poq is the midpoint of Ab and BC
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In ∆AOP and ∆ BOQ
AP= BQ. (given)
angle PAO= Angle QBO. (each 90°)
Angle AOP=angle BOQ. (V.O.A)
therefore ∆AOP =~ ∆BOQ.
Therefore OA=OB
Therefore O is midpoint of AB
I hope this helps u. please mark it brainleist
AP= BQ. (given)
angle PAO= Angle QBO. (each 90°)
Angle AOP=angle BOQ. (V.O.A)
therefore ∆AOP =~ ∆BOQ.
Therefore OA=OB
Therefore O is midpoint of AB
I hope this helps u. please mark it brainleist
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